$today = date(‘d/m/Y’); // Todays date in date/month/4 digit year format
$yesterdaydt=date(‘d/m/Y’,strtotime(“-1 days”)); // GET Yesterdays Date
The following example will subtract 3 weeks from 1998-08-14. The result will be 1998-07-24. Notice that the only difference in the code is the week statement.
The following example will subtract 3 months from 1998-08-14. The result will be 1998-05-14. Notice that the only difference in the code is the month statement.
The following example will subtract 3 years from 1998-08-14. The result will be 1995-08-14. Notice that the only difference in the code is the year statement.
There isn’t really much difference from subtracting and adding dates. To add dates, just use any of the examples above and replace the negative (-) with a positive (+) e.g. ‘+3 weeks’
You could also just do:
echo date(“Y-m-j”, strtotime(“1998-08-14 -3 days”));
(sub days, weeks, months, as needed)
This adds 2 days to the current date:
This adds 2 months to the current date:
This adds 2 years to the current date:
This subtracts 6 hours from the current date:
This subtracts 10 minutes from the current date:
If you want to change if from the current date, then simple replace the current date with the desired one…
This adds 1 year to the date 2012-11-25:
$yesterdaydt=date(‘d/m/Y’,strtotime(“-1 days”)); // GET Yesterdays Date
Subtracting days from a date
The following example will subtract 3 days from 1998-08-14. The result will be 1998-08-11.$date = "1998-08-14";
$newdate = strtotime ( '-3 day' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
Subtracting Weeks from a date
The following example will subtract 3 weeks from 1998-08-14. The result will be 1998-07-24. Notice that the only difference in the code is the week statement.
$date = "1998-08-14";
$newdate = strtotime ( '-3 week' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
Subtracting Months from a date
The following example will subtract 3 months from 1998-08-14. The result will be 1998-05-14. Notice that the only difference in the code is the month statement.
$date = "1998-08-14";
$newdate = strtotime ( '-3 month' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
Subtracting Years from a date
The following example will subtract 3 years from 1998-08-14. The result will be 1995-08-14. Notice that the only difference in the code is the year statement.
$date = "1998-08-14";
$newdate = strtotime ( '-3 year' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
Adding days, months, weeks and years from a date
There isn’t really much difference from subtracting and adding dates. To add dates, just use any of the examples above and replace the negative (-) with a positive (+) e.g. ‘+3 weeks’
You could also just do:
echo date(“Y-m-j”, strtotime(“1998-08-14 -3 days”));
(sub days, weeks, months, as needed)
This adds 2 days to the current date:
$date = date('Y-m-j');
$newdate = strtotime ( '+2 day' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
$date = date('Y-m-j');
$newdate = strtotime ( '+2 month' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
$date = date('Y-m-j');
$newdate = strtotime ( '+2 year' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
This subtracts 6 hours from the current date:
$date = date('Y-m-j');
$newdate = strtotime ( '-6 hour' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
This subtracts 10 minutes from the current date:
$date = date('Y-m-j');
$newdate = strtotime ( '-10 minute' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
If you want to change if from the current date, then simple replace the current date with the desired one…
This adds 1 year to the date 2012-11-25:
$date = date('2011-11-25');
$newdate = strtotime ( '+1 year' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
Get the Week Start Date and ENd date
Consider today is a saturday for the given example
$day = date('w'); // Gives Day of week, returns 6 if it is saturday
$sday = $day - 1; // I need only working dates mon-sat so 6-1=5
$eday = 6 - $day; // Excepting sunday in the list
$ws = date('d/m/Y', strtotime('-'.$sday.' days')); // -5 days to current date that is monday
$we = date('d/m/Y', strtotime('+'.$eday.' days')); // + 0 days to current date that is today - sat
$lastsunday = date('d/m/Y',strtotime('-'.$day.' days')); // Gives last week sunday date
$comingsunday = date('d/m/Y',strtotime('+'. 7-$day.' days')); // coming sunday
like wise we can get any day of the week , note that the return result is a string
Code for Subtracting a day from given date
$date = '09/02/2015';
$day_before = date( 'm/d/Y', strtotime( $date . ' -1 day' ) );
echo "<br/><br/>";
$db = date('d/m/Y',strtotime($day_before));
echo $db;
Code for Subtracting a day from given date
$date = '09/02/2015';
$day_before = date( 'm/d/Y', strtotime( $date . ' -1 day' ) );
echo "<br/><br/>";
$db = date('d/m/Y',strtotime($day_before));
echo $db;